Tuesday 7-9-96
The relevant section in the textbook is 17.1
Main concepts:
A series circuit is shown in the diagram above. The current flows through each resistor in turn. If the values of the three resistors are R1 = 8 ohms, R2=8 ohms, and R3 = 4 ohms, the total resistance is 8+8+4 = 20 ohms. With a 10 V battery, by V=IR the total current in the circuit is I=V/R = 10/20 = 0.5 A. The current through each resistor would be 0.5 A.
A parallel circuit is shown in the diagram above. In this case the current supplied by the battery splits up, with the amount going through each resistor depending on its resistance. If the values of the three resistors are R1 = 8 ohms, R2=8 ohms, and R3 = 4 ohms, the total resistance is found by using 1/R = 1/8 + 1/8 + 1/4 = 1/2. That gives R = 2 ohms. With a 10 V battery, by V=IR the total current in the circuit is I=V/R = 10/2 = 5 A. The individual currents can also be found using I=V/R. The voltage across each resistor is 10 V, so I1 = 10/8 = 1.25 A. I2 = 10/8 = 1.25 A. I3=10/4 = 2.5 A. Note that the currents add together to 5A, the total current.
Relevant demonstrations for this session include: